2x^2=30000

Solution for 2x^2=30000 equation:

2x^2=30000

We move all terms to the left:

2x^2-(30000)=0

a = 2; b = 0; c = -30000;
Δ = b2-4ac
Δ = 02-4·2·(-30000)
Δ = 240000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240000}=\sqrt{40000*6}=\sqrt{40000}*\sqrt{6}=200\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{6}}{2*2}=\frac{0-200\sqrt{6}}{4}
=-\frac{200\sqrt{6}}{4}
=-50\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{6}}{2*2}=\frac{0+200\sqrt{6}}{4}
=\frac{200\sqrt{6}}{4}
=50\sqrt{6}
$